30 lines
737 B
Python
30 lines
737 B
Python
import re
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def parse(markdown):
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result = ''
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for line in markdown.splitlines():
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line = re.sub(r'__(.*)__', r'<strong>\1</strong>', line)
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line = re.sub(r'_(.*)_', r'<em>\1</em>', line)
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match = re.match(r'^(#{1,6}) (.*)', line)
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if match:
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level = len(match.group(1))
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result += f'<h{level}>{match.group(2)}</h{level}>'
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continue
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match = re.match(r'\* (.*)', line)
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if match:
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if result.endswith('</ul>'):
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result = result[:-5]
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else:
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result += '<ul>'
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result += '<li>' + match.group(1) + '</li></ul>'
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continue
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result += '<p>' + line + '</p>'
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return result
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